Women's Sunday competition offering iPad
Did you know that the $55 Women's Sunday tournament is going to celebrate its third birthday this weekend? We have been going on about it a bit, officially announcing it a few days ago and writing more about past winners like Team PokerStars Pro Liv Boeree and Team Online's Adrienne "talonchick" Rowsome.
Can you blame us for being excited? It's the only tournament of its kind in all of online poker, and we tend to be a little happy that it's still going strong three years later.
One of the ways we're celebrating is with a Facebook competition. We have an iPad for the winner, and anyone can win! The contest is open to the women and men of PokerStars. All you have to do is guess how many players will register for the March 30 Women's Sunday 3rd Anniversary tournament.
Keep in mind that there will be a special $30K guarantee and $150 bounties on the members of Team PokerStars in the field. How many players will sign up?
Simply head over to our Facebook page by clicking this link or typing www.Facebook.com/PokerStarsWomen in your browser. Go to the OfferPop link and register your guess. It's that easy! You're then in the running for a fantastic iPad2!
The person who comes closest to the exact number of runners in the March 30 Women's Sunday tournament will win the iPad. If more than one person share the same guess, we'll choose the winner at random from those correct guessers.
And if you're a female PokerStars player, you can get in on the tournament itself! As we mentioned, it will have a $30K guarantee, $150 bounties on Team Pros, and three $1.10 PokerStars Women's Club tickets for every player who registers for the Women's Sunday. Oh, and you don't need $55 to register because we are offering tons of satellites all week, including daily qualifiers for only $.33 and an $11 Mega Qualifier on March 30 with 30 seats guaranteed.
Good luck, everyone! See you over on Facebook and then on PokerStars for the Women's Sunday this weekend!
Jennifer Newell is a PokerStars freelance contributor.